US2016022281A1PendingUtilityA1

Medical drill

Assignee: UNIV NAT CENTRALPriority: Apr 18, 2011Filed: Oct 7, 2015Published: Jan 28, 2016

Est. expiryApr 18, 2031(~4.7 yrs left)· nominal 20-yr term from priority

Inventors:Jason Shiang Ching Jang Pei Hua Tsai Jia Bin Li Hung-Cheng Lin Chih Chiang Fu

A61C 3/02A61B 17/1615A61B 2017/00836A61B 2017/00831A61B 17/16A61C 1/00

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References

Claims

Abstract

A medical drill is disclosed, which is made of amorphous alloy, the amorphous alloy is a Ti-based amorphous alloy which comprises titanium in 40 at % or above, wherein the tensile strength of the medical drill is 1600-2600 MPa, and the Vicker's hardness of the medical drill is 600-800.

Claims

exact text as granted — not AI-modified

What is claimed is: 
     
         1 . A medical drill made of an amorphous alloy, wherein the amorphous alloy is a Ti-based amorphous alloy which comprises titanium in 40 at % or more, and the Ti-based amorphous alloy has a tensile strength of 1600-2600 MPa and a Vickers hardness of 600-800. 
     
     
         2 . The medical drill as claimed in  claim 1 , wherein the medical drill is shaped in a pillar body, and a spiral structure is formed in a portion of the pillar body. 
     
     
         3 . The medical drill as claimed in  claim 1 , wherein the medical drill is shaped in a pillar body, and a thread is formed in a portion of the pillar body. 
     
     
         4 . The medical drill as claimed in  claim 1 , wherein the Ti-based amorphous alloy comprises titanium in 40 at % or more, copper in 30-40 at %, palladium in 10-20 at % and zirconium in 5-15 at %. 
     
     
         5 . The medical drill as claimed in  claim 1 , wherein the Ti-based amorphous alloy further comprises silicon in 1 wt % or more. 
     
     
         6 . The medical drill as claimed in  claim 1 , wherein the Ti-based amorphous alloy is represented by the following formula 5,
   Ti a Cu b Pd c Zr d Si e ,  [formula 5]
   wherein 40=&lt;a=&lt;75, 30=&lt;b=&lt;40, 10=&lt;c=&lt;20, 5=&lt;d=&lt;15, 0.05=&lt;e=&lt;2.

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