Invisible frame for automobile windshield and side windows

Abstract

Frames for an automobile windshield and side windows with improved visibility is formed by a plurality of hollow quadrilateral prisms. Each hollow quadrilateral prism includes four rigid right triangular prisms laid unsymmetrically in a V-like shape, two on each side of the V. Each rigid right triangular prism has a base triangle which is an obtuse and scalene triangle, and front and rear lateral faces which are covered with a reflective material of visible light. The front and rear lateral faces of the four right triangular prisms face each other forming an unsymmetrical channel between them, which is filled with a transparent material. The hollow quadrilateral prism reflects incident light in sequence by the reflective lateral faces of right triangular prisms. Many hollow invisible quadrilateral prisms are stacked up to form pillars for an automobile.

What is claimed is: 
     
       1. A hollow quadrilateral prism, comprising:
 first, second, third and fourth rigid right triangular prisms,
 each right triangular prism having an upper and a lower base having identical height of an obtuse and scalene triangle, 
 each right triangular prism having a rectangular front lateral face, a rectangular rear lateral face and a rectangular bottom floor, located between and perpendicular to the upper and lower bases, the obtuse triangles of the upper and lower bases flare to the bottom floor, 
 wherein the rectangular front lateral face and the rectangular rear lateral face of each right triangular prism is covered by a material that reflects visible light, 
 wherein the lower base triangles of the first to fourth right triangular prisms are on a same first plane and the upper base triangles of the four prisms are on a same second plane, which is parallel to the first plane, 
 wherein the bottom floors of the first and third right triangular prisms are on a same third plane, and the front lateral face of the first right triangular prism and the rear lateral face of the third right triangular prism are separated with a rectangular gap, 
 wherein the bottom floors of the second and fourth right triangular prisms are on the same fourth plane and immediately adjacent to each other, and the front lateral face of the second right triangular prism and the rear lateral face of the fourth right triangular prism are adjacent to each other,
 wherein the lateral edges of first and second right triangular prisms, opposite each bottom floor are on a same fifth plane, 
 wherein the lateral edges of third and fourth right triangular prisms, opposite each bottom floor are on a same sixth plane, parallel to the fifth plane, 
 
 wherein the plane perpendicular to the fifth plane and passes through an intersection line of the third and fourth planes is defined as a seventh plane on which the observer's point (also called the the bottom point of V-like shape) locates, 
 wherein an acute dihedral angle formed by the third and seventh planes is named ϕ 1 ,
 wherein the acute dihedral angle formed by the fourth and seventh is named ϕ 2 , larger than ϕ 1 , 
 
 wherein a height of the upper or lower base triangle of the right triangular prism is defined by a perpendicular distance from the bottom floor of the right triangular prism to opposite lateral edge, and wherein heights of the upper and lower base triangles of all the four right triangular prisms are identical, and
 wherein the heights of all the four right triangular prisms, defined by the length of lateral edge of the right triangular prism, are identical. 
 
 
 
     
     
       2. The hollow quadrilateral prism of  claim 1 , wherein parameters of the first to fourth triangular prisms and the relative position of four right quadrilateral prism in the first plane satisfy: 
       
         
           
             
               
                 
                   
                     
                       
                         ϕ 
                         1 
                       
                       + 
                       
                         2 
                         ⁢ 
                         
                             
                         
                         ⁢ 
                         
                           θ 
                           1 
                         
                       
                       + 
                       α 
                     
                     = 
                     
                       π 
                       2 
                     
                   
                 
                 
                   
                     Eq 
                     . 
                     
                         
                     
                     ⁢ 
                     
                       ( 
                       1 
                       ) 
                     
                   
                 
               
               
                 
                   
                     
                       
                         ϕ 
                         2 
                       
                       + 
                       
                         2 
                         ⁢ 
                         
                             
                         
                         ⁢ 
                         
                           θ 
                           2 
                         
                       
                       + 
                       α 
                     
                     = 
                     
                       π 
                       2 
                     
                   
                 
                 
                   
                     Eq 
                     . 
                     
                         
                     
                     ⁢ 
                     
                       ( 
                       2 
                       ) 
                     
                   
                 
               
               
                 
                   
                     
                       
                         θ 
                         1 
                       
                       + 
                       
                         δ 
                         1 
                       
                       + 
                       α 
                     
                     = 
                     
                       π 
                       2 
                     
                   
                 
                 
                   
                     Eq 
                     . 
                     
                         
                     
                     ⁢ 
                     
                       ( 
                       3 
                       ) 
                     
                   
                 
               
               
                 
                   
                     
                       
                         θ 
                         2 
                       
                       + 
                       
                         δ 
                         2 
                       
                       + 
                       α 
                     
                     = 
                     
                       π 
                       2 
                     
                   
                 
                 
                   
                     Eq 
                     . 
                     
                         
                     
                     ⁢ 
                     
                       ( 
                       4 
                       ) 
                     
                   
                 
               
               
                 
                   
                     
                       
                         θ 
                         1 
                         ′ 
                       
                       + 
                       
                         δ 
                         1 
                       
                       + 
                       
                         
                           α 
                           + 
                           
                             α 
                             ′ 
                           
                         
                         2 
                       
                     
                     = 
                     
                       π 
                       2 
                     
                   
                 
                 
                   
                     Eq 
                     . 
                     
                         
                     
                     ⁢ 
                     
                       ( 
                       5 
                       ) 
                     
                   
                 
               
               
                 
                   
                     
                       
                         θ 
                         2 
                         ′ 
                       
                       + 
                       
                         δ 
                         2 
                       
                       + 
                       
                         
                           α 
                           + 
                           
                             α 
                             ′ 
                           
                         
                         2 
                       
                     
                     = 
                     
                       π 
                       2 
                     
                   
                 
                 
                   
                     Eq 
                     . 
                     
                         
                     
                     ⁢ 
                     
                       ( 
                       6 
                       ) 
                     
                   
                 
               
               
                 
                   
                     
                       
                         θ 
                         1 
                         ′ 
                       
                       + 
                       
                         δ 
                         1 
                         ′ 
                       
                       + 
                       
                         α 
                         ′ 
                       
                     
                     = 
                     
                       π 
                       2 
                     
                   
                 
                 
                   
                     Eq 
                     . 
                     
                         
                     
                     ⁢ 
                     
                       ( 
                       7 
                       ) 
                     
                   
                 
               
               
                 
                   
                     
                       
                         θ 
                         2 
                         ′ 
                       
                       + 
                       
                         δ 
                         2 
                         ′ 
                       
                       + 
                       
                         α 
                         ′ 
                       
                     
                     = 
                     
                       π 
                       2 
                     
                   
                 
                 
                   
                     Eq 
                     . 
                     
                         
                     
                     ⁢ 
                     
                       ( 
                       8 
                       ) 
                     
                   
                 
               
               
                 
                   
                     
                       hcsc 
                       ⁢ 
                       
                           
                       
                       ⁢ 
                       α 
                     
                     = 
                     CD 
                   
                 
                 
                   
                     Eq 
                     . 
                     
                         
                     
                     ⁢ 
                     
                       ( 
                       9 
                       ) 
                     
                   
                 
               
               
                 
                   
                     
                       hcsc 
                       ⁢ 
                       
                           
                       
                       ⁢ 
                       
                         α 
                         ′ 
                       
                     
                     = 
                     GH 
                   
                 
                 
                   
                     Eq 
                     . 
                     
                         
                     
                     ⁢ 
                     
                       ( 
                       10 
                       ) 
                     
                   
                 
               
             
           
         
         where θ 1  is the dihedral angle of the third plane and rear lateral face of the first right triangular prism, δ 1  is the dihedral angle of the third plane and front lateral face of the first right triangular prism, 
         where θ 2  is the dihedral angle of the fourth plane and rear lateral face of the second right triangular prism, δ 2  is the dihedral angle of the fourth plane and front lateral face of the second right triangular prism, 
         where θ′ 1  is the dihedral angle of the third plane and rear lateral face of the third right triangular prism, δ′ 1  is the dihedral angle of the third plane and front lateral face of the third right triangular prism, 
         where θ′ 2  is the dihedral angle of the fourth plane and rear lateral face of the fourth right triangular prism, δ′ 2  is the dihedral angle of the fourth plane and front lateral face of the fourth right triangular prism, 
         α is the dihedral angle formed by the fifth plane and the plane determined by the lateral edge opposite the front lateral face of the first right triangular prism and the lateral edge opposite the bottom floor of the second right triangular prism, ∠BCD=∠ADC=α, 
         α′ is the dihedral angle formed by the sixth plane and the plane determined by the lateral edge opposite the front lateral face of the third right triangular prism and the lateral edge opposite the bottom floor of the fourth right triangular prism, ∠FGH=∠E′ HG=α′. 
       
     
     
       3. The hollow quadrilateral prism of  claim 1 , wherein a space between the first, second, third and fourth right triangular prisms is filled with a transparent material. 
     
     
       4. The hollow quadrilateral prism of  claim 3 , wherein the transparent material is air. 
     
     
       5. The hollow quadrilateral prism of  claim 1 , wherein each of the first to fourth right triangular prisms has either a solid or hollow interior. 
     
     
       6. A support pillar, comprising a plurality of hollow quadrilateral prism of  claim 5  stacked up. 
     
     
       7. Two support pillars, comprising a plurality of hollow quadrilateral prism of  claim 5  stacked up, all the right triangular prisms on the left of the seventh plane serve as one pillar, all the right triangular prisms of the right of the seventh plane serve as another pillar.